error C2360: initialization of ‘i’ is skipped by ‘case’ label ?
My program has an error C2360: initialization of ‘i’ is skipped by ‘case’ label.
I don’t know why. Please help me out!
thks!!
the error occurs in Division case 3.
- //Claire’s Calculator
- #include
- #include
- double pow(double x, double y);
- main()
- <
- int choice, choicee;
- const double PI = 3.14159;
- float a, b, c;
- int n, m;
- double cy;
- double x, y;
- float x_to_the_y;
- double r;
- int re, q;
- do //
- <
- cout > choice; //get choice from the user
- if ((choice 8))
- <
- cout 8));
- switch(choice)
- <
- case 1: // Addition
- cout > a;
- cout > b;
- cout > a;
- cout > b;
- cout > a;
- cout > b;
- cout > choicee;
- >
- while ((choicee 3));
- switch(choicee)
- <
- case 1: //answer as a decimal
- cout > a;
- cout > b;
- cy = a / b;
- cout > n;
- cout > m;
- n = Denom;
- m = Num;
- for (i = n * m; i > 1; i—)
- <
- if ((n % i == 0) && (m % i == 0))
- <
- n /= i;
- m /= i;
- >
- >
- cout > a;
- cout > b;
- q = a / b;
- re = (int)a % (int)b;
- cout > a;
- cout > b;
- c = a * (b / 100);
- cout > x;
- cout > y;
- x_to_the_y = pow(x, y);
- cout > r;
- cout > a;
- double pow(double x, double y);
- cout > x;
- cout > y;
- x_to_the_y = pow(x, y);
- cout 4 24503
In case 2 try using:
int n, m, i;
n, m, i= 0;
instead of:
int n, m, i = 0;
not sure why it works this way.
Hi,
I think the error is coming becos the n,m declartion in case 2 is clashing with the declartion in the beginning of the program.
Enclose the case 2 inside curly brace like this
Hi,
I don’t know about the tags. I just started today.
The variables defined at the top of the program
are in scope for the duration of the entire program.
So declaring n and m again is not necessary in case 2.
You could declare i at the top of the program and then
you may not have a problem. If you want to keep i local,
it is correct to enclose the contents of the case in curly brackerts. That makes i a local variable for case 2.
It would not hurt to enclose each case in curly brackets and define your local variables for each case, if you would like to. Anyway, whatever is at the top is in scope to the end of the program. C++ allows you to declare
your variables near the applicable code, whereas C does not. So in your case, it would not hurt to take advantage of the capabilities of C++.
case 2: //answer as a fraction
int n, m, i = 0;
etc.
break;
case 3: //answer as a number with a remainder
// error C2360: initialization of ‘i’ is skipped by ‘case’ label
cout Expand | Select | Wrap | Line Numbers
- case 2: //answer as a fraction
- <
- int n, m, i = 0;
- >
- etc.
- break;
- case 3: //answer as a number with a remainder
- // error C2360: initialization of ‘i’ is skipped by ‘case’ label
- cout Message
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Error c2360 is skipped by case label
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case labels are just jump targets; there are no case «blocks» unless you write the block yourself. The reason the restriction you mention exists is best demonstrated with an example:
It is important to remember that a switch/case is just a fancy wrapper for a bunch of gotos and labels. For example, the code above is semantically equivalent to this:
[Edited by — Sharlin on March 24, 2006 6:04:31 PM]
Quote: Form MSDN
the variable is within scope until the end of the switch statement
So it could be used outside the particular case, without initialization, which is unsafe.
Although I’m surprised this (which is basically the same) goes away with a warning only:
Great explanation, thank you. So is it preferred to use blocks for local variables within a case block, or is it best to declare it outside the switch?
Depends on the solution.
Quote: Original post by deffer
Although I’m surprised this (which is basically the same) goes away with a warning only:
*** Source Snippet Removed ***
I guess they (VS team) don’t care much about safety of ‘goto’ users.
[grin]
Suspect that’ll turn into an error with a non-POD type. While bad mojo, I believe that example is technically valid — and hence inappropriate to cause a compile error on — unless you turn on whatever flag’s required for your compiler to treat warnings as errors :-).
Quote: Original post by MaulingMonkey
Suspect that’ll turn into an error with a non-POD type. While bad mojo, I believe that example is technically valid — and hence inappropriate to cause a compile error on — unless you turn on whatever flag’s required for your compiler to treat warnings as errors :-).
Now it’s semanticly the same, but with different treatment from the compiler (VS 7.1).
Quote: Original post by MaulingMonkey
Suspect that’ll turn into an error with a non-POD type. While bad mojo, I believe that example is technically valid — and hence inappropriate to cause a compile error on — unless you turn on whatever flag’s required for your compiler to treat warnings as errors :-).
*** Source Snippet Removed ***
Now it’s semanticly the same, but with different treatment from the compiler (VS 7.1).
In the code you typed, the destructor of B is called but the constructor is not. This is . not ideal.
Basically, always do this:
«Pretend» that code needs <>s after a case statement — even more, «pretend» that code needs
<
>break;
after a case statement.
(there are rare exceptions in which you can skip the break;, but . they should be used about as carefully as you would use a goto statement.)
Initialization skipped by case label
Hi everyone,
I have worked some more on my code and this time I am getting some error that I am not able to resolve. Please help me.
The error says: «initialization skipped by case label.» Please show me how to resolve this.
Here is the code. The error has a remark in red.
Really appreciate your help.
Thanks.
- 4 Contributors 5 Replies 4K Views 7 Hours Discussion Span Latest Post 14 Years Ago Latest Post by robgeek
You error is the fundamental language mistake. It is not possible
to declare any new variable or object in the scope of the switch statement that has outside scope. ifstream input(«help.txt»); is not allowed.
Additionally, you have already declared input at the top
[4 lines below main()].
To open an output stream it is output.open(«ParkingCharges.txt»,ios::out); NOT: ofstream.output(«Parking Charges.txt», ios::out); Because you are using a class name not an instance/object (ofstream is not an object) and you are using output which is not in the class or the public base classes.
All 5 Replies
You error is the fundamental language mistake. It is not possible
to declare any new variable or object in the scope of the switch statement that has outside scope. ifstream input(«help.txt»); is not allowed.
Additionally, you have already declared input at the top
[4 lines below main()].
If you want to try this
Further, you don’t actually use input and output, but define a NEW
instance of output in the function CarParking.
Compiler errors C2300 Through C2399
The articles in this section of the documentation explain a subset of the error messages that are generated by the compiler.
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Error c2360 is skipped by case label
| PRF |
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 Шустрый Профиль Репутация: нет Здравствуйте.. помогите пожалуйста, выдает почему то ошибку, вроде бы простой код, может я чего то не замечаю?
switch(key) /* ввод матрицы смежности */ break; |
Загрузка .
выдает такую ошибку
error C2360: initialization of ‘first’ is skipped by ‘case’ label
error C2360: initialization of ‘matrix’ is skipped by ‘case’ label
помогите пожалуйста, вроде бы конструкция switch правильно использована..
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| vinter |
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 Explorer Профиль Репутация: 13
switch(key) /* ввод матрицы смежности */ break; |
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| Lazin |
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 Эксперт Профиль Репутация: 41
Это сообщение отредактировал(а) Lazin — 7.9.2008, 18:32 | |||
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| PRF |
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| Шустрый Профиль Репутация: нет спасибо большое! раньше не знал этого момента((( Это сообщение отредактировал(а) PRF — 7.9.2008, 20:41 | |||
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| UnrealMan |
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Цитата(Lazin @ 7.9.2008, 19:31  ) |
| между кейсами нельзя объявлять переменные |
Объявлять можно, инициализировать нельзя.
Это сообщение отредактировал(а) UnrealMan — 7.9.2008, 21:48
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